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8eb3cdf2bb
Assigning a typed nil to the error interface gives a non-nil value.
That breaks the common pattern `if nil != nil { ... }`.
To avoid this problem, NewError should return an interface.
28 lines
500 B
Go
28 lines
500 B
Go
package errors
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import (
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"fmt"
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"testing"
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)
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func check(fail bool) Error {
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if fail {
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return NewError("Check", "fail is true", fmt.Errorf("underlying error"))
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}
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return nil
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}
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func TestNewError(t *testing.T) {
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var err error
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err = check(true)
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if expected := "Check: fail is true: underlying error"; err == nil || err.Error() != expected {
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t.Errorf("check(true): got %v, want %v", err, expected)
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}
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err = check(false)
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if err != nil {
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t.Errorf("check(false): got %v, want nil", err)
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}
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}
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